Answer :

35 mEq of Mn²⁺ is 961.45 grams or 961,450 milligrams.

To calculate the grams and milligrams of Mn²⁺ in the solution, we need to use the molar mass of Mn²⁺ and the given amount in milliequivalents (mEq).

1. Calculate grams:

To find the grams of Mn²⁺, we'll first convert mEq to moles using the equivalent weight (EW) of Mn²⁺, which is the molar mass divided by the valence.

The molar mass of Mn²⁺ is approximately 54.94 g/mol (from the periodic table), and since Mn²⁺ has a valence of 2, the equivalent weight (EW) is 54.94/2 = 27.47 g/mEq.

So, to find the grams:

[tex]\[ \text{grams} = \text{mEq} \times \text{EW} \] \[ \text{grams} = 35 \, \text{mEq} \times 27.47 \, \text{g/mEq} \] \[ \text{grams} = 961.45 \, \text{g} \][/tex]

2. Calculate milligrams:

To find the milligrams, we'll just convert grams to milligrams.

[tex]\[ \text{milligrams} = \text{grams} \times 1000 \] \[ \text{milligrams} = 961.45 \, \text{g} \times 1000 \] \[ \text{milligrams} = 961,450 \, \text{mg} \][/tex]

So, the solution contains 961.45 grams or 961,450 milligrams of Mn²⁺.

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