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Two concentric uniform thin spherical shells have masses of 74 kg and 14 kg, with radii of 32 m and 89 m, respectively. What is the gravitational force on a particle of mass 130 kg located at:

(a) A distance of 11 m from the center of the shells: [tex]F_1 = \,? \,N[/tex]

(b) A distance of 68 m from the center of the shells: [tex]F_2 = \,? \,N[/tex]

(c) A distance of 103 m from the center of the shells: [tex]F_3 = \,? \,N[/tex]

Answer :

Answer:

a) F= 0 N, b) F = 138.8 pN
, c) F = 68.66 pN

Explanation:

The universal gravitation force is

F = G m₁ m₂ / r²


When this equation is used, the mass of a spherical body can be considered at its center, in general when using Gaussian surfaces the force is produced by the mass inside the surface. This means that if the mass this force of the point of analysis does not produce force


With these arguments we will apply them to our case

a) r = 11 m

This distance is less than the radius of the two spherical shells, so the net effect of these distributions is zero

F = 0 N


b) r = 68 m

The point is between the two shells, therefore the gravitational force is

F = G m₁ m₂ / r²

F = 6.67 10⁻¹¹ 130 74/68²

F = 13.88 10⁻¹¹ N

F = 138.8 pN

c) r = 103 m

The point is outside the two spheres, so the two exert gravitational attraction to the body as if the entire mass were in its center

F = G m₁m₂ / r² + G m₁ m₃ / r²

F = G m₁ (m₂ + m₃) / r²

F = 6.67 10⁻¹¹ 130 (14 * 74) / 103²

F = 6.67 19⁻¹¹ 130 84/103²

F = 6.8655 10⁻¹¹ N

F = 68.66 pN

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