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Higher Order Thinking

Morgan says [tex]$7 \times 0$[/tex] is equal to [tex]$7 + 0$[/tex]. Is Morgan correct? Why or why not?

Answer :

Morgan's statement that [tex]\(7 \times 0\)[/tex] is equal to [tex]\(7 + 0\)[/tex] is incorrect. Let me explain why.

1. Understanding Multiplication by Zero:
- When you multiply any number by zero, the result is always zero. This is known as the "multiplication property of zero." So, [tex]\(7 \times 0\)[/tex] equals 0.

2. Understanding Addition of Zero:
- When you add zero to any number, the result is the number itself. This is because adding zero doesn't change the value. So, [tex]\(7 + 0\)[/tex] equals 7.

3. Comparing the Two Results:
- From the above calculations, we have:
- [tex]\(7 \times 0 = 0\)[/tex]
- [tex]\(7 + 0 = 7\)[/tex]

Since 0 is not equal to 7, Morgan's statement that [tex]\(7 \times 0\)[/tex] is equal to [tex]\(7 + 0\)[/tex] is not correct.

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