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Given a DC battery with a voltage of [tex]V = 4.00 \, \text{V}[/tex] connected to a resistor [tex]R[/tex] with a current [tex]I = 3.00 \, \text{A}[/tex] through the resistor, what is the power in this circuit?

A. 15.5 W
B. 12.0 W
C. 39.4 W
D. 45.5 W
E. 8.88 W

Answer :

12.0 W

Explanation

Electric power is the rate, per unit time, at which electrical energy is transferred by an electric circuit. to find the power in the circuit we need to use the expression:

[tex]P=IV[/tex]

where P is the powe I is the current and V is the voltage

Step 1

a)Let

[tex]\begin{gathered} I=\text{ 3 Amperes} \\ V=4.0\text{ volts} \end{gathered}[/tex]

b) now,replace

[tex]\begin{gathered} P=IV \\ P=3\text{ A*4 V} \\ P=12\text{ W} \end{gathered}[/tex]

therefore, the answer is

12.0 W

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