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The atomic mass of potassium is 39.1. What is the mass of [tex]$6.02 \times 10^{23}$[/tex] atoms of potassium?

A. [tex]\quad 39.1 \, \text{mg}[/tex]
B. [tex]\quad 39.1 \, \text{g}[/tex]
C. [tex]\quad 39.1 \, \text{kg}[/tex]
D. [tex]\quad 6.02 \times 39.1 \, \text{mg}[/tex]
E. [tex]\quad 6.02 \times 39.1 \, \text{g}[/tex]

Answer :

To solve the problem of finding the mass of [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium, follow these steps:

1. Understand Avogadro's Number:
Avogadro's number, [tex]\(6.02 \times 10^{23}\)[/tex], is the number of atoms or molecules in one mole of a substance.

2. Recognize the Atomic Mass:
The atomic mass of potassium is given as 39.1. This means that one mole of potassium atoms (which is [tex]\(6.02 \times 10^{23}\)[/tex] atoms) has a mass of 39.1 grams.

3. Determine the Mass of the Given Number of Atoms:
Since [tex]\(6.02 \times 10^{23}\)[/tex] atoms is exactly one mole of potassium, the mass of these atoms corresponds to the atomic mass of one mole of potassium, which is 39.1 grams.

4. Select the Correct Answer:
Based on the explanation above, the mass of [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium is 39.1 grams.

Therefore, the correct answer is B. 39.1 g.

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