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Answer :
To multiply the polynomials [tex]\((x^2 - 5x)\)[/tex] and [tex]\((2x^2 + x - 3)\)[/tex], follow these steps:
1. Distribute each term in the first polynomial across the second polynomial:
- Multiply [tex]\(x^2\)[/tex] by each term in [tex]\((2x^2 + x - 3)\)[/tex]:
- [tex]\(x^2 \cdot 2x^2 = 2x^4\)[/tex]
- [tex]\(x^2 \cdot x = x^3\)[/tex]
- [tex]\(x^2 \cdot -3 = -3x^2\)[/tex]
- Multiply [tex]\(-5x\)[/tex] by each term in [tex]\((2x^2 + x - 3)\)[/tex]:
- [tex]\(-5x \cdot 2x^2 = -10x^3\)[/tex]
- [tex]\(-5x \cdot x = -5x^2\)[/tex]
- [tex]\(-5x \cdot -3 = 15x\)[/tex]
2. Combine all the products:
[tex]\[
2x^4 + x^3 - 3x^2 - 10x^3 - 5x^2 + 15x
\][/tex]
3. Combine like terms:
- Combine [tex]\(x^3\)[/tex] terms: [tex]\(x^3 - 10x^3 = -9x^3\)[/tex]
- Combine [tex]\(x^2\)[/tex] terms: [tex]\(-3x^2 - 5x^2 = -8x^2\)[/tex]
After combining, we have:
[tex]\[
2x^4 - 9x^3 - 8x^2 + 15x
\][/tex]
Therefore, the final product is:
[tex]\[
2x^4 - 9x^3 - 8x^2 + 15x
\][/tex]
So, the correct answer is Option D: [tex]\(2x^4 - 9x^3 - 8x^2 + 15x\)[/tex].
1. Distribute each term in the first polynomial across the second polynomial:
- Multiply [tex]\(x^2\)[/tex] by each term in [tex]\((2x^2 + x - 3)\)[/tex]:
- [tex]\(x^2 \cdot 2x^2 = 2x^4\)[/tex]
- [tex]\(x^2 \cdot x = x^3\)[/tex]
- [tex]\(x^2 \cdot -3 = -3x^2\)[/tex]
- Multiply [tex]\(-5x\)[/tex] by each term in [tex]\((2x^2 + x - 3)\)[/tex]:
- [tex]\(-5x \cdot 2x^2 = -10x^3\)[/tex]
- [tex]\(-5x \cdot x = -5x^2\)[/tex]
- [tex]\(-5x \cdot -3 = 15x\)[/tex]
2. Combine all the products:
[tex]\[
2x^4 + x^3 - 3x^2 - 10x^3 - 5x^2 + 15x
\][/tex]
3. Combine like terms:
- Combine [tex]\(x^3\)[/tex] terms: [tex]\(x^3 - 10x^3 = -9x^3\)[/tex]
- Combine [tex]\(x^2\)[/tex] terms: [tex]\(-3x^2 - 5x^2 = -8x^2\)[/tex]
After combining, we have:
[tex]\[
2x^4 - 9x^3 - 8x^2 + 15x
\][/tex]
Therefore, the final product is:
[tex]\[
2x^4 - 9x^3 - 8x^2 + 15x
\][/tex]
So, the correct answer is Option D: [tex]\(2x^4 - 9x^3 - 8x^2 + 15x\)[/tex].
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