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Answer :
Mr. Lim had 19610 dollars at first.
To find how much did Mr. Lim had at first.
Given:
Mr. Lim and Mr. Tay had $31 090 at first.
Mr. Lim donated $2390 of his money and
Mr. Tay spent half of his money on a holiday trip.
Mr. Lim had 3 times as much money as Mr. Tay.
Step 1:
Let Mr. Tay had x
Let Mr. Lim had y
x + y=31090………..(1)
Step 2:
Mr. Tay spent on holiday = x + 2390/2
Money left with Mr. Lim = y - 2390
Given,
y - 2390 = 3(x + 2390/2) .............(2)
Step 3:
Equating equation (1) and (2)
we get,
x = 11480
y = 19610
Hence, Mr. Lim has $19610, and Mr. Tay had $11480 dollars at first.
To learn how to calculate the amount spent, refer,
- https://brainly.com/question/2263981
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Answer:
Mr.Lim had 19610 dollars, and Mr.Tay had 11480 dollars at first.
Step-by-step explanation:
