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Select the correct answer.

Paul is gathering data about moss growth in a local forest. He measured an area of 11 square centimeters on one particular tree and will come back in 6 months to measure the growth of the moss. If the area covered by moss multiplies by one and a half times each month, approximately how much area will the moss cover when Paul returns?

A. [tex]99.1 \, \text{cm}^2[/tex]

B. [tex]14.7 \, \text{cm}^2[/tex]

C. [tex]125.3 \, \text{cm}^2[/tex]

D. [tex]16.5 \, \text{cm}^2[/tex]

Answer :

To solve this problem, we need to calculate the area of moss growth over a period of 6 months. We start with an initial area of 11 square centimeters and the moss grows at a rate of multiplying by one and a half times each month.

Here's how we can determine the total area after 6 months:

1. Initial Area: We know that the initial area covered by moss is 11 square centimeters.

2. Growth Rate: The moss increases by one and a half times, meaning for each month, the area is multiplied by 1.5.

3. Number of Months: We are calculating the growth over a period of 6 months.

4. Calculate the Final Area:
- Use the formula for exponential growth:
[tex]\[
\text{Final Area} = \text{Initial Area} \times (\text{Growth Rate})^{\text{Number of Months}}
\][/tex]
- Plug in the known values:
[tex]\[
\text{Final Area} = 11 \times (1.5)^6
\][/tex]

5. Calculate Step-by-Step:
- First, compute [tex]\( (1.5)^6 \)[/tex].
- Multiply this result by the initial area of 11 cm² to find the final area.

The final result is approximately 125.3 cm².

Hence, the correct answer is:
C. [tex]\(125.3 \, \text{cm}^2\)[/tex]

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