College

We appreciate your visit to Determine the allowable gross load on a 2m x 2m foundation embedded at a depth of 1 5m The properties of the soil are as. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!

Determine the allowable gross load on a 2m x 2m foundation embedded at a depth of 1.5m. The properties of the soil are as follows:

- \(\phi = 30°\)
- \(c = 2 \, \text{kPa}\)
- \(\gamma = 17 \, \text{kN/m}^3\)

Use the General Bearing Capacity Equation and a Factor of Safety (FS) = 3.0.

Answer :

The allowable gross load on a 2m x 2m foundation embedded at a depth of 1.5m can be determined using the general bearing capacity equation. The given properties of the soil are: angle of internal friction (ϕ) = 30°, cohesion (c) = 2 kPa, and unit weight (γ) = 17 kN/m³. Using the provided values, the allowable gross load is calculated to be 803.9 kPa.

The allowable gross load on a foundation can be determined using the general bearing capacity equation. The equation is given by Qa = cNc+qNq+0.5ρBNγ.

Where:

c is the cohesion of the soil

q is the overburden pressure at the foundation depth

ρ is the unit weight of soil

B is the width of the foundation

Nc, Nq, and Nγ are bearing capacity factors

First, we need to calculate the overburden pressure at the foundation depth:

q = γ × depth = 17 kN/m³ × 1.5m = 25.5 kPa

Next, we can plug in the values into the general bearing capacity equation:

Qa = 2 kPa × Nc + 25.5 kPa × Nq + 0.5 × 17 kN/m³ × 2m × Nγ

We need to determine the bearing capacity factors for this particular soil condition. Since the soil properties are provided, we can use Terzaghi's bearing capacity factor charts to find the values for the angle of internal friction (ϕ) = 30°:

Nc = 9.4

Nq = 9.4

Nγ = 16.1

Finally, we can substitute these values into the equation and calculate the allowable gross load:

Qa = 2 kPa × 9.4 + 25.5 kPa × 9.4 + 0.5 × 17 kN/m³ × 2m × 16.1

Qa = 18.8 kPa + 239.7 kPa + 545.4 kPa = 803.9 kPa

Therefore, the allowable gross load on the foundation is 803.9 kPa.

Learn more about the topic of Calculating allowable gross load on a foundation here: https://brainly.com/question/20720056

#SPJ11

Thanks for taking the time to read Determine the allowable gross load on a 2m x 2m foundation embedded at a depth of 1 5m The properties of the soil are as. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada