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Multiply.

[tex]\left(x^4+1\right)\left(3x^2+9x+2\right)[/tex]

Options:
A. [tex]x^4 + 3x^2 + 9x + 3[/tex]
B. [tex]3x^6 + 9x^5 + 2x^4 + 3x^2 + 9x + 2[/tex]
C. [tex]3x^7 + 9x^6 + 2x^5[/tex]
D. [tex]3x^8 + 9x^4 + 2x^4 + 3x^2 + 9x + 2[/tex]

Answer :

To solve the multiplication problem [tex]\((x^4 + 1)(3x^2 + 9x + 2)\)[/tex], we will expand the expression by distributing each term from the first polynomial across each term of the second polynomial.

Here’s how we do it step-by-step:

1. Distribute [tex]\(x^4\)[/tex] across [tex]\(3x^2 + 9x + 2\)[/tex]:

- [tex]\(x^4 \cdot 3x^2 = 3x^{6}\)[/tex]
- [tex]\(x^4 \cdot 9x = 9x^{5}\)[/tex]
- [tex]\(x^4 \cdot 2 = 2x^{4}\)[/tex]

So from distributing [tex]\(x^4\)[/tex], we get: [tex]\(3x^6 + 9x^5 + 2x^4\)[/tex]

2. Distribute [tex]\(1\)[/tex] across [tex]\(3x^2 + 9x + 2\)[/tex]:

- [tex]\(1 \cdot 3x^2 = 3x^2\)[/tex]
- [tex]\(1 \cdot 9x = 9x\)[/tex]
- [tex]\(1 \cdot 2 = 2\)[/tex]

So from distributing [tex]\(1\)[/tex], we get: [tex]\(3x^2 + 9x + 2\)[/tex]

3. Combine all the terms:

Now, we add together all these parts from above:

[tex]\[
3x^6 + 9x^5 + 2x^4 + 3x^2 + 9x + 2
\][/tex]

This is the expanded form of [tex]\((x^4 + 1)(3x^2 + 9x + 2)\)[/tex].

Therefore, the result is [tex]\(3x^6 + 9x^5 + 2x^4 + 3x^2 + 9x + 2\)[/tex]. This represents the fully expanded product of the given polynomials.

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