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Answer :
The faucet leaks water at three different rates per hour. We first convert each rate to liters:
1. Deciliters to liters:
Since [tex]$1$[/tex] deciliter equals [tex]$0.1$[/tex] liter,
[tex]$$9 \text{ deciliters} = 9 \times 0.1 = 0.9 \text{ liters}.$$[/tex]
2. Centiliters to liters:
Since [tex]$1$[/tex] centiliter equals [tex]$0.01$[/tex] liter,
[tex]$$9 \text{ centiliters} = 9 \times 0.01 = 0.09 \text{ liters}.$$[/tex]
3. Milliliters to liters:
Since [tex]$1$[/tex] milliliter equals [tex]$0.001$[/tex] liter,
[tex]$$2 \text{ milliliters} = 2 \times 0.001 = 0.002 \text{ liters}.$$[/tex]
Next, we add these amounts to find the total leakage per hour:
[tex]$$
\text{Leakage per hour} = 0.9 + 0.09 + 0.002 = 0.992 \text{ liters per hour}.
$$[/tex]
Since the faucet leaks for [tex]$3$[/tex] hours, the total amount of water leaked is:
[tex]$$
\text{Total leakage} = 0.992 \times 3 = 2.976 \text{ liters}.
$$[/tex]
Thus, after [tex]$3$[/tex] hours, a total of [tex]$2.976$[/tex] liters of water will have leaked.
1. Deciliters to liters:
Since [tex]$1$[/tex] deciliter equals [tex]$0.1$[/tex] liter,
[tex]$$9 \text{ deciliters} = 9 \times 0.1 = 0.9 \text{ liters}.$$[/tex]
2. Centiliters to liters:
Since [tex]$1$[/tex] centiliter equals [tex]$0.01$[/tex] liter,
[tex]$$9 \text{ centiliters} = 9 \times 0.01 = 0.09 \text{ liters}.$$[/tex]
3. Milliliters to liters:
Since [tex]$1$[/tex] milliliter equals [tex]$0.001$[/tex] liter,
[tex]$$2 \text{ milliliters} = 2 \times 0.001 = 0.002 \text{ liters}.$$[/tex]
Next, we add these amounts to find the total leakage per hour:
[tex]$$
\text{Leakage per hour} = 0.9 + 0.09 + 0.002 = 0.992 \text{ liters per hour}.
$$[/tex]
Since the faucet leaks for [tex]$3$[/tex] hours, the total amount of water leaked is:
[tex]$$
\text{Total leakage} = 0.992 \times 3 = 2.976 \text{ liters}.
$$[/tex]
Thus, after [tex]$3$[/tex] hours, a total of [tex]$2.976$[/tex] liters of water will have leaked.
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