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Answer :
Given:
Number of white counters = 10
Number of black counters = 6
Number of green counters = 4
Required: Probability
Explanation:
Total number of counters
[tex]\begin{gathered} =10+6+4 \\ =20 \end{gathered}[/tex](a) Number of counters which are white or green
[tex]\begin{gathered} =10+4 \\ =14 \end{gathered}[/tex]Probability of drawing a white counter or a green counter
[tex]\begin{gathered} =\frac{14}{20} \\ =\frac{7}{10} \end{gathered}[/tex](b) Number of counters which are black or green
[tex]\begin{gathered} =6+4 \\ =10 \end{gathered}[/tex]Probability of drawing a black counter or a green co
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Rewritten by : Barada
The probabilities of drawing a white or green, a black or green, and not a green counter are 7/10, 1/2, and 4/5, respectively.
When dealing with probabilities in a setting where we are drawing objects from a container, like counters or marbles, we calculate the probability of an event by dividing the number of ways that event can happen by the total number of possible outcomes.
(a) To find the probability of drawing a white counter or a green counter, we add the number of white counters to the number of green counters, and divide by the total number of counters. So it's (10 white + 4 green) / (10 white + 6 black + 4 green) = 14/20 = 7/10.
(b) For a black counter or a green counter, the calculation is (6 black + 4 green) / (10 white + 6 black + 4 green) = 10/20 = 1/2.
(c) To calculate the probability of not drawing a green counter, we look at the total minus the green counters, so (10 white + 6 black) / (10 white + 6 black + 4 green) = 16/20 = 4/5.
