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Answer :
To calculate the resistance of a metal wire, we use the formula:
[tex]\[ R = \rho \times \frac{L}{A} \][/tex]
where:
- [tex]\( R \)[/tex] is the resistance,
- [tex]\( \rho \)[/tex] is the resistivity of the material,
- [tex]\( L \)[/tex] is the length of the wire,
- [tex]\( A \)[/tex] is the area of cross-section of the wire.
Given in the problem:
- The length [tex]\( L \)[/tex] of the wire is 2 meters.
- The area of cross-section [tex]\( A \)[/tex] is [tex]\( 1.55 \times 10^{-6} \, \text{m}^2 \)[/tex].
- The resistivity [tex]\( \rho \)[/tex] of the metal is [tex]\( 2.8 \times 10^{-8} \, \Omega \cdot \text{m} \)[/tex].
Let's substitute these values into the formula:
[tex]\[ R = 2.8 \times 10^{-8} \, \Omega \cdot \text{m} \times \frac{2 \, \text{m}}{1.55 \times 10^{-6} \, \text{m}^2} \][/tex]
After calculating the above expression, the resistance [tex]\( R \)[/tex] is approximately:
[tex]\[ R = 0.0361 \, \Omega \][/tex]
So, the resistance of the metal wire is approximately 0.0361 ohms.
[tex]\[ R = \rho \times \frac{L}{A} \][/tex]
where:
- [tex]\( R \)[/tex] is the resistance,
- [tex]\( \rho \)[/tex] is the resistivity of the material,
- [tex]\( L \)[/tex] is the length of the wire,
- [tex]\( A \)[/tex] is the area of cross-section of the wire.
Given in the problem:
- The length [tex]\( L \)[/tex] of the wire is 2 meters.
- The area of cross-section [tex]\( A \)[/tex] is [tex]\( 1.55 \times 10^{-6} \, \text{m}^2 \)[/tex].
- The resistivity [tex]\( \rho \)[/tex] of the metal is [tex]\( 2.8 \times 10^{-8} \, \Omega \cdot \text{m} \)[/tex].
Let's substitute these values into the formula:
[tex]\[ R = 2.8 \times 10^{-8} \, \Omega \cdot \text{m} \times \frac{2 \, \text{m}}{1.55 \times 10^{-6} \, \text{m}^2} \][/tex]
After calculating the above expression, the resistance [tex]\( R \)[/tex] is approximately:
[tex]\[ R = 0.0361 \, \Omega \][/tex]
So, the resistance of the metal wire is approximately 0.0361 ohms.
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