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Answer :
To solve the equation [tex]\(\frac{1}{2}(x-14)+11=\frac{1}{2} x-(x-4)\)[/tex], we can follow Karissa's correct work step by step:
1. Simplify Both Sides of the Equation:
Start with the original equation:
[tex]\[
\frac{1}{2}(x-14) + 11 = \frac{1}{2} x - (x-4)
\][/tex]
Simplify the left side:
[tex]\[
\frac{1}{2}(x-14) + 11 = \frac{1}{2}x - 7 + 11
\][/tex]
[tex]\[
= \frac{1}{2}x + 4
\][/tex]
Simplify the right side:
[tex]\[
\frac{1}{2} x - (x - 4) = \frac{1}{2}x - x + 4
\][/tex]
[tex]\[
= -\frac{1}{2}x + 4
\][/tex]
So the equation simplifies to:
[tex]\[
\frac{1}{2}x + 4 = -\frac{1}{2}x + 4
\][/tex]
2. Subtract 4 from Both Sides:
[tex]\[
\frac{1}{2}x + 4 - 4 = -\frac{1}{2}x + 4 - 4
\][/tex]
Simplifying both sides gives:
[tex]\[
\frac{1}{2}x = -\frac{1}{2}x
\][/tex]
3. Add [tex]\(\frac{1}{2}x\)[/tex] to Both Sides:
[tex]\[
\frac{1}{2}x + \frac{1}{2}x = 0
\][/tex]
Combine like terms:
[tex]\[
x = 0
\][/tex]
Therefore, the solution to the equation is [tex]\(x = 0\)[/tex].
1. Simplify Both Sides of the Equation:
Start with the original equation:
[tex]\[
\frac{1}{2}(x-14) + 11 = \frac{1}{2} x - (x-4)
\][/tex]
Simplify the left side:
[tex]\[
\frac{1}{2}(x-14) + 11 = \frac{1}{2}x - 7 + 11
\][/tex]
[tex]\[
= \frac{1}{2}x + 4
\][/tex]
Simplify the right side:
[tex]\[
\frac{1}{2} x - (x - 4) = \frac{1}{2}x - x + 4
\][/tex]
[tex]\[
= -\frac{1}{2}x + 4
\][/tex]
So the equation simplifies to:
[tex]\[
\frac{1}{2}x + 4 = -\frac{1}{2}x + 4
\][/tex]
2. Subtract 4 from Both Sides:
[tex]\[
\frac{1}{2}x + 4 - 4 = -\frac{1}{2}x + 4 - 4
\][/tex]
Simplifying both sides gives:
[tex]\[
\frac{1}{2}x = -\frac{1}{2}x
\][/tex]
3. Add [tex]\(\frac{1}{2}x\)[/tex] to Both Sides:
[tex]\[
\frac{1}{2}x + \frac{1}{2}x = 0
\][/tex]
Combine like terms:
[tex]\[
x = 0
\][/tex]
Therefore, the solution to the equation is [tex]\(x = 0\)[/tex].
Thanks for taking the time to read Karissa begins to solve the equation tex frac 1 2 x 14 11 frac 1 2 x x 4 tex Her work is correct and. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
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