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Answer :
To find the force exerted by the snowmobile when Sully accelerates, we can follow these steps:
1. Identify the Given Values:
- Initial velocity ([tex]\(v_i\)[/tex]) = 10 meters/second
- Final velocity ([tex]\(v_f\)[/tex]) = 16 meters/second
- Total mass ([tex]\(m\)[/tex]) = 280 kilograms
- Time ([tex]\(t\)[/tex]) = 10 seconds
2. Calculate the Acceleration:
- Acceleration ([tex]\(a\)[/tex]) can be calculated using the formula:
[tex]\[
a = \frac{v_f - v_i}{t}
\][/tex]
- Substitute the given values:
[tex]\[
a = \frac{16 - 10}{10} = \frac{6}{10} = 0.6 \text{ meters/second}^2
\][/tex]
3. Calculate the Force:
- Use the equation for force:
[tex]\[
F = m \times a
\][/tex]
- Substitute the mass and the calculated acceleration:
[tex]\[
F = 280 \times 0.6 = 168 \text{ Newtons}
\][/tex]
So, the correct answer is B. 168 N.
1. Identify the Given Values:
- Initial velocity ([tex]\(v_i\)[/tex]) = 10 meters/second
- Final velocity ([tex]\(v_f\)[/tex]) = 16 meters/second
- Total mass ([tex]\(m\)[/tex]) = 280 kilograms
- Time ([tex]\(t\)[/tex]) = 10 seconds
2. Calculate the Acceleration:
- Acceleration ([tex]\(a\)[/tex]) can be calculated using the formula:
[tex]\[
a = \frac{v_f - v_i}{t}
\][/tex]
- Substitute the given values:
[tex]\[
a = \frac{16 - 10}{10} = \frac{6}{10} = 0.6 \text{ meters/second}^2
\][/tex]
3. Calculate the Force:
- Use the equation for force:
[tex]\[
F = m \times a
\][/tex]
- Substitute the mass and the calculated acceleration:
[tex]\[
F = 280 \times 0.6 = 168 \text{ Newtons}
\][/tex]
So, the correct answer is B. 168 N.
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