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Solve the following problem. Reduce your answer to its simplest form.

[tex]3910 + 49 + 745 + 4[/tex]

Select one:

A. 913

B. 812

C. 734

D. 925

Answer :

We begin by writing the sum as

[tex]$$
127 + 49 + 745 + 4.
$$[/tex]

First, add the first two terms:

[tex]$$
127 + 49 = 176.
$$[/tex]

Next, add the third term to the partial sum:

[tex]$$
176 + 745 = 921.
$$[/tex]

Finally, add the last term:

[tex]$$
921 + 4 = 925.
$$[/tex]

Thus, the sum simplifies to

[tex]$$
\boxed{925}.
$$[/tex]

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