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Answer :
We are given the following information:
- Initial velocity: [tex]$u = 10\ \text{m/s}$[/tex]
- Final velocity: [tex]$v = 16\ \text{m/s}$[/tex]
- Time taken: [tex]$t = 10\ \text{s}$[/tex]
- Mass: [tex]$m = 280\ \text{kg}$[/tex]
Step 1: Calculate the acceleration using the formula
[tex]$$
a = \frac{v - u}{t}.
$$[/tex]
Substitute the given values:
[tex]$$
a = \frac{16 - 10}{10} = \frac{6}{10} = 0.6\ \text{m/s}^2.
$$[/tex]
Step 2: Use the force equation
[tex]$$
F = m \cdot a.
$$[/tex]
Substitute the values of mass and acceleration:
[tex]$$
F = 280 \times 0.6 = 168\ \text{N}.
$$[/tex]
Thus, the force is [tex]$168\ \text{N}$[/tex], which corresponds to answer option B.
- Initial velocity: [tex]$u = 10\ \text{m/s}$[/tex]
- Final velocity: [tex]$v = 16\ \text{m/s}$[/tex]
- Time taken: [tex]$t = 10\ \text{s}$[/tex]
- Mass: [tex]$m = 280\ \text{kg}$[/tex]
Step 1: Calculate the acceleration using the formula
[tex]$$
a = \frac{v - u}{t}.
$$[/tex]
Substitute the given values:
[tex]$$
a = \frac{16 - 10}{10} = \frac{6}{10} = 0.6\ \text{m/s}^2.
$$[/tex]
Step 2: Use the force equation
[tex]$$
F = m \cdot a.
$$[/tex]
Substitute the values of mass and acceleration:
[tex]$$
F = 280 \times 0.6 = 168\ \text{N}.
$$[/tex]
Thus, the force is [tex]$168\ \text{N}$[/tex], which corresponds to answer option B.
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