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Answer :
We start with the formula for momentum:
$$
p = m \cdot v
$$
where:
- \( p \) is the momentum,
- \( m \) is the mass,
- \( v \) is the velocity.
We need to solve for the mass \( m \). Rearranging the formula gives:
$$
m = \frac{p}{v}
$$
Given the values:
- \( p = 125000 \, \text{kg}\cdot\text{m/s} \)
- \( v = 22.0 \, \text{m/s} \)
Substitute these numbers into the equation:
$$
m = \frac{125000 \, \text{kg}\cdot\text{m/s}}{22.0 \, \text{m/s}}
$$
Performing the division:
$$
m \approx 5681.82 \, \text{kg}
$$
Rounding to an answer that fits the provided options, the mass of the truck is approximately:
$$
5680 \, \text{kg}
$$
$$
p = m \cdot v
$$
where:
- \( p \) is the momentum,
- \( m \) is the mass,
- \( v \) is the velocity.
We need to solve for the mass \( m \). Rearranging the formula gives:
$$
m = \frac{p}{v}
$$
Given the values:
- \( p = 125000 \, \text{kg}\cdot\text{m/s} \)
- \( v = 22.0 \, \text{m/s} \)
Substitute these numbers into the equation:
$$
m = \frac{125000 \, \text{kg}\cdot\text{m/s}}{22.0 \, \text{m/s}}
$$
Performing the division:
$$
m \approx 5681.82 \, \text{kg}
$$
Rounding to an answer that fits the provided options, the mass of the truck is approximately:
$$
5680 \, \text{kg}
$$
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