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Answer :
Final answer:
The empirical formula of the compound is AlCl3
Explanation:
The empirical formula of a compound shows the simplest ratio of atoms present in the compound. To determine the empirical formula, we need to find the moles of each element.
First, we calculate the moles of aluminum using its molar mass of 26.98 g/mol:
Moles of aluminum = 10.0 g / 26.98 g/mol = 0.370 mol
Next, we calculate the moles of chlorine using its molar mass of 35.45 g/mol:
Moles of chlorine = 39.4 g / 35.45 g/mol = 1.11 mol
To find the simplest ratio, we divide the moles of each element by the smallest number of moles. In this case, the smallest number of moles is 0.370 mol:
Aluminum: 0.370 mol / 0.370 mol = 1
Chlorine: 1.11 mol / 0.370 mol = 3
Therefore, the empirical formula of the compound is AlCl3.
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