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Answer :
Answer:
500 N
Explanation:
Given;
Mass of the car, M = 1000 kg
initial speed of the car, u = 0 m/s
Final speed of the car, v = 60 m/s
Time, t = 1 min = 60 s
Now,
Force, F is given as:
F = Ma
where,
a is the acceleration
From the Newton's equation of motion, we have
v = u + at
on substituting the values, we get
60 = 0 + a × 60
or
a = 1 m/s²
Thus,
Force = 1000 × 1 = 1000 N
now,
this force will be equal to the friction force provided by the rear wheels
let the friction force on a single rear wheel be 'f'
thus,
2f = 1000 N
or
f = 500 N
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