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Suppose the scores of seven members of a women's golf team are [tex]$68, 62, 60, 64, 70, 66, 72$[/tex]. Find the mean, median, and midrange.

a. Mean [tex]$=64$[/tex], median [tex]$=64$[/tex], midrange [tex]$=64$[/tex]

b. Mean [tex]$=65$[/tex], median [tex]$=64$[/tex], midrange [tex]$=66$[/tex]

c. Mean [tex]$=66$[/tex], median [tex]$=77$[/tex], midrange [tex]$=65$[/tex]

d. Mean [tex]$=66$[/tex], median [tex]$=66$[/tex], midrange [tex]$=66$[/tex]

Please select the best answer from the choices provided:

A

B

C

D

Answer :

We start with the given scores:

[tex]$$68,\;62,\;60,\;64,\;70,\;66,\;72.$$[/tex]

Step 1: Calculate the Mean

The mean is given by

[tex]$$\text{Mean} = \frac{\text{sum of the scores}}{\text{number of scores}}.$$[/tex]

First, we add the scores:

[tex]$$68 + 62 + 60 + 64 + 70 + 66 + 72 = 462.$$[/tex]

Since there are 7 scores, the mean is

[tex]$$\text{Mean} = \frac{462}{7} = 66.$$[/tex]

Step 2: Calculate the Median

To find the median, first sort the scores in ascending order:

[tex]$$60,\;62,\;64,\;66,\;68,\;70,\;72.$$[/tex]

Since there are 7 scores, the median is the fourth score in the sorted list. Thus,

[tex]$$\text{Median} = 66.$$[/tex]

Step 3: Calculate the Midrange

The midrange is the average of the minimum and maximum scores. The smallest score is 60, and the largest is 72. Hence,

[tex]$$\text{Midrange} = \frac{60 + 72}{2} = \frac{132}{2} = 66.$$[/tex]

Conclusion

The computed values are:

- Mean: 66
- Median: 66
- Midrange: 66

Thus, the correct option is:

[tex]$$\boxed{\text{D}}.$$[/tex]

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