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Graph of 2 polygons:

Polygon 1 at A(6, 6), B(6, 8), C(8, 8), D(8, 4), E(10, 4), F(12, 2), G(4, 2), H(4, 4).

Polygon 2 at M(12, -6), N(12, -8), O(14, -8), P(14, -4), Q(16, -4), R(18, -2), S(10, -2), T(10, -4).

Which statement is true?

A. A sequence of translations will map MNOPQRST onto ABCDEFGH.
B. A sequence of rigid transformations will map MNOPQRST onto ABCDEFGH.
C. A sequence of rotations will map MNOPQRST onto ABCDEFGH.
D. A sequence of reflections will map MNOPQRST onto ABCDEFGH.

Answer :

A sequence of reflections will map MNOPQRST onto ABCDEFGH (option d).

To determine whether a sequence of transformations can map Polygon 2 (MNOPQRST) onto Polygon 1 (ABCDEFGH), we need to analyze the given points and see if we can apply translations, rigid transformations, rotations, or reflections to achieve this.

Let's examine the options one by one:

A. A sequence of translations will map MNOPQRST onto ABCDEFGH.

This is not possible because translations alone cannot change the relative orientation of the polygons.

B. A sequence of rigid transformations will map MNOPQRST onto ABCDEFGH.

This is possible. A rigid transformation can include a combination of translations, rotations, and reflections, but it preserves the shape and size of the polygons. If we can perform a sequence of rigid transformations that align the two polygons, it will work.

C. A sequence of rotations will map MNOPQRST onto ABCDEFGH.

This is not possible because rotations alone cannot transform Polygon 2 into Polygon 1 due to the differences in their shapes and sizes.

D. A sequence of reflections will map MNOPQRST onto ABCDEFGH.

This is possible. Reflections can be used to flip and mirror the polygons. Depending on the sequence of reflections, you can align Polygon 2 with Polygon 1.

So, the correct answer is D. A sequence of reflections will map MNOPQRST onto ABCDEFGH.

To know more about sequence:

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