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Match each fraction on the left with an equivalent fraction on the right.

[tex]\[

\begin{array}{ll}

\frac{1}{2} & \frac{17}{34} \\

\frac{2}{3} & \frac{36}{54} \\

\frac{3}{4} & \frac{18}{24} \\

\frac{4}{5} & \frac{32}{40} \\

\end{array}

\][/tex]

Answer :

Sure, let's match each fraction on the left with its equivalent fraction on the right by simplifying them to check for equivalency.

1. Matching [tex]\(\frac{1}{2}\)[/tex]:
- Simplify the fractions on the right.
- [tex]\(\frac{17}{34}\)[/tex] simplifies to [tex]\(\frac{1}{2}\)[/tex] because 17 is half of 34.
- Therefore, [tex]\(\frac{1}{2}\)[/tex] matches with [tex]\(\frac{17}{34}\)[/tex].

2. Matching [tex]\(\frac{2}{3}\)[/tex]:
- We need to find a fraction from the right that simplifies to [tex]\(\frac{2}{3}\)[/tex].
- [tex]\(\frac{32}{48}\)[/tex] simplifies to [tex]\(\frac{2}{3}\)[/tex] because both numerator and denominator are divisible by 16.
- Thus, [tex]\(\frac{2}{3}\)[/tex] matches with [tex]\(\frac{32}{48}\)[/tex].

3. Matching [tex]\(\frac{3}{4}\)[/tex]:
- Let's simplify the fractions on the right to match with [tex]\(\frac{3}{4}\)[/tex].
- [tex]\(\frac{18}{24}\)[/tex] simplifies to [tex]\(\frac{3}{4}\)[/tex] because both numbers are divisible by 6.
- So, [tex]\(\frac{3}{4}\)[/tex] matches with [tex]\(\frac{18}{24}\)[/tex].

4. Matching [tex]\(\frac{4}{5}\)[/tex]:
- Find a fraction on the right that simplifies to [tex]\(\frac{4}{5}\)[/tex].
- [tex]\(\frac{36}{45}\)[/tex] simplifies to [tex]\(\frac{4}{5}\)[/tex] because both numbers are divisible by 9.
- Therefore, [tex]\(\frac{4}{5}\)[/tex] matches with [tex]\(\frac{36}{45}\)[/tex].

Here is the matched list:
- [tex]\(\frac{1}{2}\)[/tex] with [tex]\(\frac{17}{34}\)[/tex]
- [tex]\(\frac{2}{3}\)[/tex] with [tex]\(\frac{32}{48}\)[/tex]
- [tex]\(\frac{3}{4}\)[/tex] with [tex]\(\frac{18}{24}\)[/tex]
- [tex]\(\frac{4}{5}\)[/tex] with [tex]\(\frac{36}{45}\)[/tex]

These are the equivalent fractions from the two lists.

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