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8. How many representative partioles are in 4.3 moles of Radium?


9. How many representative particles are in 4.7 mols of Barium Sulfide (BaS)?


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8 How many representative partioles are in 4 3 moles of Radium 9 How many representative particles are in 4 7 mols of Barium Sulfide

Answer :

There are 2.589 x 10^24 representative particles in 4.3 moles of Radium.

There are 5.6308 x 10^24 representative particles in 4.7 moles of Barium Sulfide.

What is the number of particles?

The Avogadro's number represents the number of particles in one mole of a substance. The value of Avogadro's number is approximately 6.022 x 10^23 particles per mole.

Therefore, to find the number of representative particles in 4.3 moles of Radium, we can multiply the Avogadro's number by the number of moles:

Number of particles = 6.022 x 10^23 particles/mol x 4.3 mol

Number of particles = 2.589 x 10^24 particles

Barium Sulfide (BaS) has one barium atom and one sulfur atom per molecule. To find the number of representative particles in 4.7 moles of BaS, we can use the Avogadro's number and the number of molecules:

Number of molecules = 4.7 mol x (6.022 x 10^23 molecules/mol)

Number of molecules = 2.8154 x 10^24 molecules

Since each molecule of BaS contains one barium atom and one sulfur atom, we can find the total number of representative particles (atoms and ions) by multiplying the number of molecules by 2:

Number of representative particles = 2.8154 x 10^24 molecules x 2

Number of representative particles = 5.6308 x 10^24 particles

Learn more about number of particles at: https://brainly.com/question/29367909

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