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Answer :
Final answer:
The heat energy required to increase the temperature of a 1kg aluminum block by 75°C is 67.5 kJ.
Explanation:
To calculate the heat energy required, we can use the formula Q = mcΔt, where Q is the heat energy, m is the mass of the aluminum block, c is the specific heat of aluminum, and Δt is the change in temperature.
Given that the mass of the aluminum block is 1kg, the specific heat of aluminum is 900 J/kg°C, and the change in temperature is 75°C, we can substitute these values into the formula:
Q = (1kg)(900 J/kg°C)(75°C) = 67,500 J = 67.5 kJ
Therefore, the correct answer is 67.5 kJ.
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