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Answer :
To find the mass of [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium, we should understand a few key concepts:
1. Atomic Mass and Moles: The atomic mass of potassium is given as 39.1. This is the mass of one mole of potassium atoms, which is equivalent to Avogadro's number of atoms ([tex]\(6.02 \times 10^{23}\)[/tex] atoms).
2. Avogadro's Number: Avogadro's number ([tex]\(6.02 \times 10^{23}\)[/tex]) represents the number of atoms or molecules in one mole of a substance.
3. Molar Mass: Because the molar mass of potassium is 39.1 grams per mole, this means that one mole of potassium atoms (which is [tex]\(6.02 \times 10^{23}\)[/tex] atoms) has a mass of 39.1 grams.
Given these points, we can conclude that [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium have a mass of 39.1 grams.
Therefore, the correct answer is:
B. 39.1 g
1. Atomic Mass and Moles: The atomic mass of potassium is given as 39.1. This is the mass of one mole of potassium atoms, which is equivalent to Avogadro's number of atoms ([tex]\(6.02 \times 10^{23}\)[/tex] atoms).
2. Avogadro's Number: Avogadro's number ([tex]\(6.02 \times 10^{23}\)[/tex]) represents the number of atoms or molecules in one mole of a substance.
3. Molar Mass: Because the molar mass of potassium is 39.1 grams per mole, this means that one mole of potassium atoms (which is [tex]\(6.02 \times 10^{23}\)[/tex] atoms) has a mass of 39.1 grams.
Given these points, we can conclude that [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium have a mass of 39.1 grams.
Therefore, the correct answer is:
B. 39.1 g
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