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Select the correct answer.

Each month, Barry makes three transactions in his checking account:
- He deposits [tex]$\$700$[/tex] from his paycheck.
- He withdraws [tex]$\$150$[/tex] to buy gas for his car.
- He withdraws [tex]$\$400$[/tex] for other expenses.

If his account balance is [tex]$\$1,900$[/tex] at the end of the 1st month, which recursive equation models Barry's account balance at the end of month [tex]m[/tex]?

A. [tex]f(1) = 1,900[/tex]
[tex]f(n) = f(n-1) + 700[/tex], for [tex]n \geq 2[/tex]

B. [tex]f(1) = 1,900[/tex]
[tex]f(n) = f(n-1) + 150[/tex], for [tex]n \geq 2[/tex]

C. [tex]f(1) = 1,900[/tex]
[tex]f(n) = f(n-1) - 150[/tex], for [tex]n \geq 2[/tex]

D. [tex]f(1) = 1,900[/tex]
[tex]f(n) = 150 \cdot f(n-1)[/tex], for [tex]n \geq 2[/tex]

Answer :

To solve the problem of finding the recursive equation that models Barry's account balance at the end of each month, let's break down his transactions step-by-step.

1. Initial Balance:
- At the end of the 1st month, Barry has a balance of [tex]$1,900 in his checking account. So, we start with:
\[
f(1) = 1,900
\]

2. Monthly Transactions:
- Each month, Barry makes the following transactions:
- He deposits $[/tex]700 from his paycheck.
- He withdraws [tex]$150 to buy gas.
- He withdraws $[/tex]400 for other expenses.

3. Net Change in Balance Each Month:
- To determine the effect of these transactions on his account balance, we calculate the net change as follows:
[tex]\[
\text{Net Change} = \text{Deposits} - (\text{Withdrawals for Gas} + \text{Withdrawals for Other Expenses})
\][/tex]
[tex]\[
\text{Net Change} = 700 - (150 + 400)
\][/tex]
[tex]\[
\text{Net Change} = 700 - 550 = 150
\][/tex]

4. Forming the Recursive Equation:
- Now that we know the net change per month is $150, we can form a recursive equation to model Barry's account balance at the end of each month:
- At month [tex]\( n \)[/tex], the balance is the previous month's balance plus the net change:
[tex]\[
f(n) = f(n-1) + 150, \text{ for } n \geq 2
\][/tex]

5. Selecting the Correct Option:
- Based on the steps above, we conclude that the recursive equation matching these conditions is:
- [tex]\( f(1) = 1,900 \)[/tex]
- [tex]\( f(n) = f(n-1) + 150, \text{ for } n \geq 2 \)[/tex]

This matches option A, which is the correct answer.

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