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Suppose that a gumball machine contains 12 red, 15 green, 21 blue, 9 yellow, and 3 white gumballs in total. One gumball is randomly selected. Can you find the probability for each event?

Question 1: What is the probability of not selecting a green gumball?

A. [tex]\frac{45}{60} = \frac{3}{4}[/tex]
B. [tex]\frac{15}{60} = \frac{1}{4}[/tex]
C. 15

Answer :

The total number of gumballs is calculated by adding together all the gumballs:

[tex]$$
12 + 15 + 21 + 9 + 3 = 60.
$$[/tex]

Since there are 15 green gumballs, the number of gumballs that are not green is:

[tex]$$
60 - 15 = 45.
$$[/tex]

The probability of not selecting a green gumball is the ratio of non-green gumballs to the total number of gumballs:

[tex]$$
\frac{45}{60} = \frac{3}{4}.
$$[/tex]

Thus, the probability for not selecting a green gumball is [tex]$\frac{3}{4}$[/tex], which corresponds to option A: [tex]$\frac{45}{60}=\frac{3}{4}$[/tex].

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