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Answer :
A wall less than or equal to 14.7 m in height is the highest the player can clear.
How to calculate height?
Use the kinematic equations of motion to solve the problem. First, we can find the time it takes for the ball to travel 99.1 m horizontally:
d = vt
t = d / v
t = 99.1 m / 36.2 m/s
t ≈ 2.74 s
Now, use the vertical motion equation to find the maximum height the ball reaches:
y = yo + vot + (1/2)at²
where:
yo = 0.996 m (initial height)
vo = v sinθ = 36.2 m/s x sin(30°) ≈ 18.1 m/s (initial vertical velocity)
a = -9.81 m/s² (acceleration due to gravity, pointing downward)
t = 2.74 s (time of flight)
y = 0.996 m + 18.1 m/s x 2.74 s + (1/2) x (-9.81 m/s²) x (2.74 s)²
y ≈ 14.7 m
Therefore, the tallest wall the player can clear is a wall with a height less than or equal to 14.7 m.
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