We appreciate your visit to Writing and solving a real world problem given an equation First complete the story below so that it can be represented by the equation tex. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
Below is a step-by-step explanation:
1. We are given the equation
[tex]$$3500 - 25x = 3000 - 15.$$[/tex]
2. This equation models the following situation:
- Pool A: It started with [tex]$3500$[/tex] liters of water and is losing water at a rate of [tex]$25$[/tex] liters per minute.
- Pool B: It started with [tex]$3000$[/tex] liters of water and had [tex]$15$[/tex] liters removed (a one-time removal). After the removal, the amount of water in Pool B is
[tex]$$3000 - 15.$$[/tex]
- The equation sets the condition that after [tex]$x$[/tex] minutes, the amount of water left in Pool A will be equal to the amount of water remaining in Pool B.
3. First, calculate the amount of water in Pool B after the removal:
[tex]$$3000 - 15 = 2985.$$[/tex]
So, Pool B has [tex]$2985$[/tex] liters remaining.
4. Now, rewrite the equation with this value:
[tex]$$3500 - 25x = 2985.$$[/tex]
5. To solve for [tex]$x$[/tex], subtract [tex]$3500$[/tex] from both sides:
[tex]$$-25x = 2985 - 3500.$$[/tex]
6. Compute the right-hand side:
[tex]$$2985 - 3500 = -515,$$[/tex]
so
[tex]$$-25x = -515.$$[/tex]
7. Divide both sides by [tex]$-25$[/tex] to isolate [tex]$x$[/tex]:
[tex]$$x = \frac{-515}{-25} = \frac{515}{25}.$$[/tex]
8. Finally, compute the value:
[tex]$$x = 20.6.$$[/tex]
Thus, after [tex]$20.6$[/tex] minutes, the amount of water in Pool A will be equal to the water remaining in Pool B.
1. We are given the equation
[tex]$$3500 - 25x = 3000 - 15.$$[/tex]
2. This equation models the following situation:
- Pool A: It started with [tex]$3500$[/tex] liters of water and is losing water at a rate of [tex]$25$[/tex] liters per minute.
- Pool B: It started with [tex]$3000$[/tex] liters of water and had [tex]$15$[/tex] liters removed (a one-time removal). After the removal, the amount of water in Pool B is
[tex]$$3000 - 15.$$[/tex]
- The equation sets the condition that after [tex]$x$[/tex] minutes, the amount of water left in Pool A will be equal to the amount of water remaining in Pool B.
3. First, calculate the amount of water in Pool B after the removal:
[tex]$$3000 - 15 = 2985.$$[/tex]
So, Pool B has [tex]$2985$[/tex] liters remaining.
4. Now, rewrite the equation with this value:
[tex]$$3500 - 25x = 2985.$$[/tex]
5. To solve for [tex]$x$[/tex], subtract [tex]$3500$[/tex] from both sides:
[tex]$$-25x = 2985 - 3500.$$[/tex]
6. Compute the right-hand side:
[tex]$$2985 - 3500 = -515,$$[/tex]
so
[tex]$$-25x = -515.$$[/tex]
7. Divide both sides by [tex]$-25$[/tex] to isolate [tex]$x$[/tex]:
[tex]$$x = \frac{-515}{-25} = \frac{515}{25}.$$[/tex]
8. Finally, compute the value:
[tex]$$x = 20.6.$$[/tex]
Thus, after [tex]$20.6$[/tex] minutes, the amount of water in Pool A will be equal to the water remaining in Pool B.
Thanks for taking the time to read Writing and solving a real world problem given an equation First complete the story below so that it can be represented by the equation tex. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada
