We appreciate your visit to In certain deep parts of the oceans the pressure of sea water P in pounds per square foot at a depth of d feet below. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
Therefore , the solution of given problem of equation comes out to be
P is equal to 12 pounds per square foot.
Define equation.
Comparable to a balance scale, an equation. The equation (or scale) is out of balance if we add or subtract variable from one side. We also Must keep the "scale" (or equation) balanced while solving math equations such that both parts are always equal as expression are equal.
Here,
P= p = 12 + 4/9d is the equation that describes the relationship between the pressure,
p, of sea water in some deep ocean regions and the depth, d, below the surface.
Where
In pounds per square foot, p.
in feet is d
1) At a depth, seawater has a pressure of 85 pounds per square foot.
85 = 12 + 4/9d
4.9d/9 = 85 - 12 = 73
By xing it out, it becomes
4.9d = 73 × 9 = 657
d = 657/4.9
d = 134.1 feet
2) At 85 feet just below water's surface, the pressure of saltwater is
p = 12 + 4/9 × 85 = 12 + 4/765
P is equal to 12 pounds per square foot.
Therefore , the solution of given problem of equation comes out to be
P is equal to 12 pounds per square foot.
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