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Answer :
Sure, let's solve the problem step by step!
We're dealing with an arithmetic progression (AP) with a sequence given as [tex]\(4, x, 0\)[/tex].
### Step 1: Find the value of [tex]\(x\)[/tex].
1. Determine the common difference [tex]\(d\)[/tex]:
- The sequence is given as [tex]\(4, x, 0\)[/tex].
- In an AP, the difference between consecutive terms is constant (this is the common difference).
- Using the third term, which is 0, and the first term, which is 4, we can set up the equation for the third term:
[tex]\[
0 = 4 + 2d
\][/tex]
- Solve for [tex]\(d\)[/tex]:
[tex]\[
2d = 0 - 4 \quad \Rightarrow \quad 2d = -4 \quad \Rightarrow \quad d = -2
\][/tex]
2. Calculate [tex]\(x\)[/tex] using the common difference:
- The second term [tex]\(x\)[/tex] is calculated using the first term and the common difference:
[tex]\[
x = 4 + d
\][/tex]
- Substitute [tex]\(d = -2\)[/tex] into the equation:
[tex]\[
x = 4 - 2 = 2
\][/tex]
### Step 2: Formula for the [tex]\(k\)[/tex]-th term of the AP.
The formula for the [tex]\(n\)[/tex]-th term ([tex]\(a_n\)[/tex]) of an arithmetic progression with first term [tex]\(a_1\)[/tex] and common difference [tex]\(d\)[/tex] is:
[tex]\[
a_k = a_1 + (k-1) \cdot d
\][/tex]
For our sequence, [tex]\(a_1 = 4\)[/tex] and [tex]\(d = -2\)[/tex].
### Step 3: Find the number of terms if the last term is 20.
We are given the last term as -20. We use the formula for the [tex]\(n\)[/tex]-th term and set it equal to -20:
[tex]\[
-20 = 4 + (n-1) \cdot (-2)
\][/tex]
1. Rearrange the equation to solve for [tex]\(n\)[/tex]:
[tex]\[
-20 = 4 - 2(n-1)
\][/tex]
[tex]\[
-20 = 4 - 2n + 2
\][/tex]
[tex]\[
-20 = 6 - 2n
\][/tex]
[tex]\[
-20 - 6 = -2n
\][/tex]
[tex]\[
-26 = -2n
\][/tex]
[tex]\[
n = \frac{-26}{-2} = 13
\][/tex]
Therefore, there are 13 terms in the arithmetic progression where the last term is -20.
This provides a detailed computation for all parts of the question.
We're dealing with an arithmetic progression (AP) with a sequence given as [tex]\(4, x, 0\)[/tex].
### Step 1: Find the value of [tex]\(x\)[/tex].
1. Determine the common difference [tex]\(d\)[/tex]:
- The sequence is given as [tex]\(4, x, 0\)[/tex].
- In an AP, the difference between consecutive terms is constant (this is the common difference).
- Using the third term, which is 0, and the first term, which is 4, we can set up the equation for the third term:
[tex]\[
0 = 4 + 2d
\][/tex]
- Solve for [tex]\(d\)[/tex]:
[tex]\[
2d = 0 - 4 \quad \Rightarrow \quad 2d = -4 \quad \Rightarrow \quad d = -2
\][/tex]
2. Calculate [tex]\(x\)[/tex] using the common difference:
- The second term [tex]\(x\)[/tex] is calculated using the first term and the common difference:
[tex]\[
x = 4 + d
\][/tex]
- Substitute [tex]\(d = -2\)[/tex] into the equation:
[tex]\[
x = 4 - 2 = 2
\][/tex]
### Step 2: Formula for the [tex]\(k\)[/tex]-th term of the AP.
The formula for the [tex]\(n\)[/tex]-th term ([tex]\(a_n\)[/tex]) of an arithmetic progression with first term [tex]\(a_1\)[/tex] and common difference [tex]\(d\)[/tex] is:
[tex]\[
a_k = a_1 + (k-1) \cdot d
\][/tex]
For our sequence, [tex]\(a_1 = 4\)[/tex] and [tex]\(d = -2\)[/tex].
### Step 3: Find the number of terms if the last term is 20.
We are given the last term as -20. We use the formula for the [tex]\(n\)[/tex]-th term and set it equal to -20:
[tex]\[
-20 = 4 + (n-1) \cdot (-2)
\][/tex]
1. Rearrange the equation to solve for [tex]\(n\)[/tex]:
[tex]\[
-20 = 4 - 2(n-1)
\][/tex]
[tex]\[
-20 = 4 - 2n + 2
\][/tex]
[tex]\[
-20 = 6 - 2n
\][/tex]
[tex]\[
-20 - 6 = -2n
\][/tex]
[tex]\[
-26 = -2n
\][/tex]
[tex]\[
n = \frac{-26}{-2} = 13
\][/tex]
Therefore, there are 13 terms in the arithmetic progression where the last term is -20.
This provides a detailed computation for all parts of the question.
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