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A 41 kg mass is pushed across a carpeted floor with a force of 196 N. There is a -32.0 N force due to friction.

What is the acceleration of the mass?

[tex]a = [?] \, \text{m/s}^2[/tex]

Answer :

We start by determining the net force acting on the mass. The total force is the sum of the applied force and the friction force. In equation form, this is:

[tex]$$ F_{\text{net}} = F_{\text{applied}} + F_{\text{friction}} $$[/tex]

Substituting the given values:

[tex]$$ F_{\text{net}} = 196\, \text{N} + (-32.0\, \text{N}) = 164.0\, \text{N} $$[/tex]

Next, we use Newton's second law, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration:

[tex]$$ F_{\text{net}} = m \cdot a $$[/tex]

Solving for acceleration ([tex]$a$[/tex]), we get:

[tex]$$ a = \frac{F_{\text{net}}}{m} $$[/tex]

Substitute the known values into the equation:

[tex]$$ a = \frac{164.0\, \text{N}}{41\, \text{kg}} $$[/tex]

Simplifying the expression:

[tex]$$ a = 4.0\, \text{m/s}^2 $$[/tex]

Thus, the acceleration of the mass is:

[tex]$$ a = 4.0\, \text{m/s}^2 $$[/tex]

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