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The population, [tex]p[/tex], of a town after [tex]t[/tex] years is represented using the equation [tex]p = 10000(1.04)^{-t}[/tex]. Which of the following is an equivalent expression?

A. [tex]p = 10000\left(\frac{1}{25}\right)^t[/tex]

B. [tex]p = 10000\left(\frac{25}{26}\right)^t[/tex]

C. [tex]p = 10000\left(\frac{26}{25}\right)^t[/tex]

D. [tex]p = 10000\left(\frac{25}{1}\right)^t[/tex]

Answer :

To find an equivalent expression for the given population equation [tex]\( p = 10000(1.04)^{-t} \)[/tex], let's break down the equation step by step:

1. Understanding the Original Expression:
The original expression is [tex]\( p = 10000(1.04)^{-t} \)[/tex]. The negative exponent indicates that we can rewrite this expression using the reciprocal of the base. Specifically, [tex]\( (1.04)^{-t} \)[/tex] is the same as [tex]\( \left(\frac{1}{1.04}\right)^{t} \)[/tex].

2. Calculate the Reciprocal:
We need to find the reciprocal of 1.04, which is [tex]\( \frac{1}{1.04} \)[/tex]. Calculating this gives us approximately 0.961538.

3. Simplify the Fraction:
The decimal 0.961538 can be expressed as a fraction. This fraction is equivalent to [tex]\( \frac{25}{26} \)[/tex]. Therefore, [tex]\( \left(\frac{1}{1.04}\right)^{t} \)[/tex] can be rewritten as [tex]\( \left(\frac{25}{26}\right)^{t} \)[/tex].

4. Substitute Back into the Expression:
Replace [tex]\( (1.04)^{-t} \)[/tex] in the original equation with [tex]\( \left(\frac{25}{26}\right)^{t} \)[/tex]. This gives us the equivalent expression:
[tex]\[
p = 10000\left(\frac{25}{26}\right)^{t}
\][/tex]

5. Identify the Correct Choice:
From the list of options given, the equivalent expression is:
[tex]\[
p = 10000\left(\frac{25}{26}\right)^{t}
\][/tex]

So, the correct answer is:
[tex]\[
p = 10000\left(\frac{25}{26}\right)^{t}
\][/tex]

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