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Suppose the scores of seven members of a women's golf team are 68, 62, 60, 64, 70, 66, and 64. Calculate the mean, median, and midrange.

a. Mean [tex]$=64$[/tex], median [tex]$=64$[/tex], midrange [tex]$=64$[/tex]
b. Mean [tex]$=65$[/tex], median [tex]$=64$[/tex], midrange [tex]$=66$[/tex]
c. Mean [tex]$=66$[/tex], median [tex]$=77$[/tex], midrange [tex]$=65$[/tex]
d. Mean [tex]$=66$[/tex], median [tex]$=66$[/tex], midrange [tex]$=66$[/tex]

Please select the best answer from the choices provided:
A
B
C
D

Answer :

Let's solve the question step-by-step by calculating each of the required statistics: mean, median, and midrange for the given golf scores.

Given scores of the team are: 68, 62, 60, 64, 70, 66, and 64.

### 1. Calculating the Mean

The mean (average) is calculated by adding all the scores together and then dividing by the number of scores.

[tex]\[ \text{Mean} = \frac{68 + 62 + 60 + 64 + 70 + 66 + 64}{7} \][/tex]

Carrying out the addition:

[tex]\[ 68 + 62 + 60 + 64 + 70 + 66 + 64 = 454 \][/tex]

Now, divide by the number of scores (7):

[tex]\[ \text{Mean} = \frac{454}{7} = 64.857 \][/tex]

This approximates to 64.86 when rounded appropriately.

### 2. Calculating the Median

The median is the middle score when all the scores are arranged in ascending order. Let's order the scores:

60, 62, 64, 64, 66, 68, 70

Since there are 7 scores, the median will be the 4th score:

So, the median is 64.

### 3. Calculating the Midrange

The midrange is calculated as the average of the highest and lowest scores.

- The lowest score is 60.
- The highest score is 70.

[tex]\[ \text{Midrange} = \frac{60 + 70}{2} = \frac{130}{2} = 65 \][/tex]

### Conclusion

Now that we have our calculations:

- Mean ≈ 64.86
- Median = 64
- Midrange = 65

Comparing with the options:

- (a) Mean = 64, Median = 64, Midrange = 64
- (b) Mean = 65, Median = 64, Midrange = 66
- (c) Mean = 66, Median = 77, Midrange = 65
- (d) Mean = 66, Median = 66, Midrange = 66

The calculated values do not exactly match the given answer options precisely but approximate closest to option (b) considering potential rounding of the mean to whole numbers and average observations. Thus, option (b) is the most consistent with the calculations and is in the correct ballpark range.

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