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Answer :
Answer:
The change in velocity was about [tex]9.84~\text{m/s}[/tex]
Explanation:
Step 1: Understand which formulas to use
The problem has the quantities: mass, force, time and change in velocity, and they are all already in their standard form/
We know that change in velocity divided by time equals to acceleration:
[tex]a=\frac{v-v_{0}}{t}[/tex]
Another formula that involves acceleration, mass and force is:
[tex]F=m\times a[/tex]
Step 2: Do the calculations:
The time is said to be [tex]8.3~\text{s}[/tex], so the acceleration will be:
[tex]a=\frac{v-v_{0}}{8.3}[/tex]
Substitute this value and the value for force, mass into the other formula:
[tex]F=m\times a\\115=97\times \frac{v-v_{0}}{8.3}[/tex]
[tex]v-v_{0}[/tex] denotes the change in velocity, so we will have to make it the subject.
[tex]115=97\times \frac{v-v_{0}}{8.3}\\\\\frac{115}{97}=\frac{v-v_{0}}{8.3}\\\\\frac{115}{97}\times 8.3 =v-v_{0}\\\\v-v_{0}\approx 9.84[/tex]
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