Answer :

To find the mass of HCl present in 825 mL of a 1.25 M solution, we can follow a step-by-step approach:

1. Convert Volume to Liters:
- The given volume is 825 mL. To convert milliliters to liters, divide by 1000:
[tex]\[
825 \text{ mL} = \frac{825}{1000} = 0.825 \text{ L}
\][/tex]

2. Calculate the Number of Moles:
- Molarity (M) is defined as the number of moles of solute per liter of solution. We are given that the solution is 1.25 M. To find the number of moles of HCl:
[tex]\[
\text{Moles of HCl} = \text{Molarity} \times \text{Volume in liters} = 1.25 \, \text{mol/L} \times 0.825 \, \text{L} = 1.03125 \, \text{moles}
\][/tex]

3. Determine the Mass:
- The molar mass of HCl is given as 36.46 g/mol. To find the mass of HCl in grams, multiply the number of moles by the molar mass:
[tex]\[
\text{Mass of HCl} = \text{Moles of HCl} \times \text{Molar Mass of HCl} = 1.03125 \, \text{moles} \times 36.46 \, \text{g/mol} \approx 37.61 \, \text{g}
\][/tex]

Therefore, the mass of HCl present in 825 mL of a 1.25 M solution is approximately 37.61 grams.

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Rewritten by : Barada