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A steel reinforcing rod is 12 ft long and [tex]$1^{\prime \prime}$[/tex] in diameter. If a cubic foot of steel weighs 490 lb, how much does the rod weigh (to the nearest pound)?

A. 128
B. 32
C. 769
D. 4,616

Answer :

To determine the weight of a steel reinforcing rod that is 12 feet long and 1 inch in diameter, we can follow these steps:

1. Convert the Diameter to Feet:
- The diameter of the rod is given in inches (1 inch). We need to convert this to feet since the length is in feet.
- There are 12 inches in a foot. So, the diameter in feet is [tex]\( \frac{1}{12} \)[/tex] feet.

2. Calculate the Radius:
- The radius is half of the diameter. Therefore,
[tex]\[
\text{Radius} = \frac{1 \text{ inch in feet}}{2} = \frac{1}{24} \text{ feet}.
\][/tex]

3. Determine the Volume of the Rod:
- The rod is a cylinder, so we use the formula for the volume of a cylinder: [tex]\( V = \pi r^2 h \)[/tex], where [tex]\( r \)[/tex] is the radius and [tex]\( h \)[/tex] is the height (or length).
- Substitute the values:
[tex]\[
V = \pi \times \left(\frac{1}{24}\right)^2 \times 12.
\][/tex]

4. Calculate the Weight:
- The weight is found by multiplying the volume by the weight of one cubic foot of steel.
- We have the weight per cubic foot as 490 pounds.
- Calculate the weight:
[tex]\[
\text{Weight} = V \times 490.
\][/tex]

After performing these calculations, we find that the weight of the rod is approximately 32 pounds. Therefore, the rod weighs 32 pounds to the nearest pound.

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