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Answer :
Final answer:
To calculate the mass of Au produced when Au₂S₃ is reduced with excess H₂, use the balanced chemical equation and molar masses.
Explanation:
To calculate the mass of Au produced when 0.0500 mol of Au₂S₃ is reduced with excess H₂, we need to use the balanced chemical equation and molar masses.
The balanced equation is:
Au₂S₃ + 6H₂ → 2Au + 3H₂S
The molar mass of Au₂S₃ is 322.10 g/mol. From the equation, we can see that 2 moles of Au are produced for every mole of Au₂S₃.
Therefore, the mass of Au produced is:
(0.0500 mol Au₂S₃) x (2 mol Au / 1 mol Au₂S₃) x (197.0 g Au / 1 mol Au) = 19.7 g Au
Learn more about Calculating mass of a product in a chemical reaction here:
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