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Answer :
We are given the following data for odometer readings ([tex]$x$[/tex]) and retail values ([tex]$y$[/tex]):
[tex]\[
\begin{array}{|c|c|}
\hline
\text{Odometer Reading } (x) & \text{Retail Value } (y) \\
\hline
13000 & 52525 \\
\hline
18000 & 51625 \\
\hline
20000 & 51350 \\
\hline
25000 & 50325 \\
\hline
29000 & 49875 \\
\hline
32000 & 49225 \\
\hline
\end{array}
\][/tex]
We now explain the steps for finding the answers.
──────────────────────────────
Step (a): Least-Squares Line
To find the least-squares line of the form
[tex]\[
\hat{y} = a + b x,
\][/tex]
we compute the slope [tex]$b$[/tex] and intercept [tex]$a$[/tex] using the standard formulas:
[tex]\[
b = \frac{n\sum (xy) - \left(\sum x\right)\left(\sum y\right)}{n\sum{x^2} - \left(\sum x\right)^2}, \quad
a = \overline{y} - b \, \overline{x},
\][/tex]
where [tex]$n$[/tex] is the number of data points.
After carrying out the computations and rounding the values to two decimal places, the resulting equation is
[tex]\[
\hat{y} = 54734.53 - 0.17 x.
\][/tex]
Since this is a linear equation, the degree of the polynomial is 1.
──────────────────────────────
Step (b): Predicting the Retail Value at 30000 Miles
To predict the retail value when the odometer reading is [tex]$x = 30000$[/tex], substitute into the equation:
[tex]\[
\hat{y} = 54734.53 - 0.17(30000).
\][/tex]
Performing the multiplication:
[tex]\[
0.17 \times 30000 = 5100,
\][/tex]
so
[tex]\[
\hat{y} \approx 54734.53 - 5100 = 49634.53.
\][/tex]
Rounding to the nearest \[tex]$100 gives a predicted value of
\[
\$[/tex]49600.
\]
──────────────────────────────
Step (c): Linear Correlation Coefficient
The linear correlation coefficient [tex]$r$[/tex] is calculated by
[tex]\[
r = \frac{\sum \left(x - \overline{x}\right)\left(y - \overline{y}\right)}{\sqrt{\sum \left(x - \overline{x}\right)^2 \sum \left(y - \overline{y}\right)^2}}.
\][/tex]
After doing the appropriate computations and rounding to four decimal places, we obtain
[tex]\[
r = -0.9979.
\][/tex]
──────────────────────────────
Step (d): Interpretation of the Negative Correlation
A negative linear correlation coefficient indicates that as the odometer reading increases, the retail value of the vehicle tends to decrease. In other words, higher mileage is associated with a lower retail value.
──────────────────────────────
Summary of Answers
(a) The equation of the least-squares line is
[tex]\[
\hat{y} = 54734.53 - 0.17x \quad (\text{with a polynomial degree of } 1).
\][/tex]
(b) For an odometer reading of [tex]$30000$[/tex], the predicted retail value is approximately
[tex]\[
\$49600.
\][/tex]
(c) The linear correlation coefficient is
[tex]\[
r = -0.9979.
\][/tex]
(d) The negative correlation coefficient means that as the odometer reading increases, the retail value decreases.
These are the detailed steps and results for this problem.
[tex]\[
\begin{array}{|c|c|}
\hline
\text{Odometer Reading } (x) & \text{Retail Value } (y) \\
\hline
13000 & 52525 \\
\hline
18000 & 51625 \\
\hline
20000 & 51350 \\
\hline
25000 & 50325 \\
\hline
29000 & 49875 \\
\hline
32000 & 49225 \\
\hline
\end{array}
\][/tex]
We now explain the steps for finding the answers.
──────────────────────────────
Step (a): Least-Squares Line
To find the least-squares line of the form
[tex]\[
\hat{y} = a + b x,
\][/tex]
we compute the slope [tex]$b$[/tex] and intercept [tex]$a$[/tex] using the standard formulas:
[tex]\[
b = \frac{n\sum (xy) - \left(\sum x\right)\left(\sum y\right)}{n\sum{x^2} - \left(\sum x\right)^2}, \quad
a = \overline{y} - b \, \overline{x},
\][/tex]
where [tex]$n$[/tex] is the number of data points.
After carrying out the computations and rounding the values to two decimal places, the resulting equation is
[tex]\[
\hat{y} = 54734.53 - 0.17 x.
\][/tex]
Since this is a linear equation, the degree of the polynomial is 1.
──────────────────────────────
Step (b): Predicting the Retail Value at 30000 Miles
To predict the retail value when the odometer reading is [tex]$x = 30000$[/tex], substitute into the equation:
[tex]\[
\hat{y} = 54734.53 - 0.17(30000).
\][/tex]
Performing the multiplication:
[tex]\[
0.17 \times 30000 = 5100,
\][/tex]
so
[tex]\[
\hat{y} \approx 54734.53 - 5100 = 49634.53.
\][/tex]
Rounding to the nearest \[tex]$100 gives a predicted value of
\[
\$[/tex]49600.
\]
──────────────────────────────
Step (c): Linear Correlation Coefficient
The linear correlation coefficient [tex]$r$[/tex] is calculated by
[tex]\[
r = \frac{\sum \left(x - \overline{x}\right)\left(y - \overline{y}\right)}{\sqrt{\sum \left(x - \overline{x}\right)^2 \sum \left(y - \overline{y}\right)^2}}.
\][/tex]
After doing the appropriate computations and rounding to four decimal places, we obtain
[tex]\[
r = -0.9979.
\][/tex]
──────────────────────────────
Step (d): Interpretation of the Negative Correlation
A negative linear correlation coefficient indicates that as the odometer reading increases, the retail value of the vehicle tends to decrease. In other words, higher mileage is associated with a lower retail value.
──────────────────────────────
Summary of Answers
(a) The equation of the least-squares line is
[tex]\[
\hat{y} = 54734.53 - 0.17x \quad (\text{with a polynomial degree of } 1).
\][/tex]
(b) For an odometer reading of [tex]$30000$[/tex], the predicted retail value is approximately
[tex]\[
\$49600.
\][/tex]
(c) The linear correlation coefficient is
[tex]\[
r = -0.9979.
\][/tex]
(d) The negative correlation coefficient means that as the odometer reading increases, the retail value decreases.
These are the detailed steps and results for this problem.
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