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Answer :
Answer:
Explanation:
If t be the time of fall of drops from a height of 181 s ,
181 = 1/2 g t²
t = 6 s approx
There are 4 drops in vertical line , one touching the floor, one at 181 m height on the verge of falling down , and two drops in mid air.
The time interval between dripping of two consecutive drops
= 6 / 3
2 s
time duration of fall of second drop = 2 x 2 = 4 s
Position of drop below nozzle
= 1/2 g x 4²
= 78.4 m
b )
Time duration of fall of third drop
= 2 s
Position of drop below nozzle
= 1/2 9.8 x 2²
= 19.6 m
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