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Answer :
To determine the number of moles in 151 grams of sulfur dioxide ([tex]\( \text{SO}_2 \)[/tex]), follow these steps:
1. Calculate the molar mass of [tex]\(\text{SO}_2\)[/tex]. The atomic masses are:
- Sulfur ([tex]\(S\)[/tex]): [tex]\(32.07 \, \text{g/mol}\)[/tex]
- Oxygen ([tex]\(O\)[/tex]): [tex]\(16.00 \, \text{g/mol}\)[/tex]
The molar mass of [tex]\(\text{SO}_2\)[/tex] is given by:
[tex]$$
M = 32.07 + 2(16.00) = 32.07 + 32.00 = 64.07 \, \text{g/mol}
$$[/tex]
2. Use the formula for moles:
[tex]$$
\text{moles} = \frac{\text{mass}}{\text{molar mass}}
$$[/tex]
Substituting the values:
[tex]$$
\text{moles} = \frac{151 \, \text{g}}{64.07 \, \text{g/mol}} \approx 2.3568 \, \text{mol}
$$[/tex]
3. Round the result to three significant figures:
[tex]$$
2.3568 \, \text{mol} \approx 2.36 \, \text{mol}
$$[/tex]
Thus, 151 grams of [tex]\(\text{SO}_2\)[/tex] is equal to [tex]\(2.36\)[/tex] moles.
1. Calculate the molar mass of [tex]\(\text{SO}_2\)[/tex]. The atomic masses are:
- Sulfur ([tex]\(S\)[/tex]): [tex]\(32.07 \, \text{g/mol}\)[/tex]
- Oxygen ([tex]\(O\)[/tex]): [tex]\(16.00 \, \text{g/mol}\)[/tex]
The molar mass of [tex]\(\text{SO}_2\)[/tex] is given by:
[tex]$$
M = 32.07 + 2(16.00) = 32.07 + 32.00 = 64.07 \, \text{g/mol}
$$[/tex]
2. Use the formula for moles:
[tex]$$
\text{moles} = \frac{\text{mass}}{\text{molar mass}}
$$[/tex]
Substituting the values:
[tex]$$
\text{moles} = \frac{151 \, \text{g}}{64.07 \, \text{g/mol}} \approx 2.3568 \, \text{mol}
$$[/tex]
3. Round the result to three significant figures:
[tex]$$
2.3568 \, \text{mol} \approx 2.36 \, \text{mol}
$$[/tex]
Thus, 151 grams of [tex]\(\text{SO}_2\)[/tex] is equal to [tex]\(2.36\)[/tex] moles.
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