We appreciate your visit to The table below shows the times taken for a group of athletes to finish a 200 m race Work out the percentage of the athletes. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
To solve the problem of finding the percentage of athletes who took more than 26 seconds to finish the 200 m race, follow these steps:
1. Identify the relevant intervals:
- We need to consider athletes who took more than 26 seconds. This includes the time intervals [tex]$26 < t \leq 28$[/tex] and [tex]$28 < t \leq 30$[/tex].
2. Count the number of athletes in each interval:
- For [tex]$26 < t \leq 28$[/tex], there are 8 athletes.
- For [tex]$28 < t \leq 30$[/tex], there are 9 athletes.
3. Add the number of athletes in these intervals:
- Total athletes taking more than 26 seconds = 8 (from [tex]$26 < t \leq 28$[/tex]) + 9 (from [tex]$28 < t \leq 30$[/tex]) = 17 athletes.
4. Find the total number of athletes:
- Sum the frequencies of all intervals:
- [tex]$22 < t \leq 24$[/tex]: 3 athletes
- [tex]$24 < t \leq 26$[/tex]: 5 athletes
- [tex]$26 < t \leq 28$[/tex]: 8 athletes
- [tex]$28 < t \leq 30$[/tex]: 9 athletes
- Total athletes = 3 + 5 + 8 + 9 = 25 athletes.
5. Calculate the percentage of athletes who took more than 26 seconds:
- Use the formula for percentage:
[tex]\[
\text{Percentage} = \left(\frac{\text{Number of athletes who took more than 26 seconds}}{\text{Total number of athletes}}\right) \times 100
\][/tex]
- Substitute the values into the formula:
[tex]\[
\text{Percentage} = \left(\frac{17}{25}\right) \times 100 = 68.0\%
\][/tex]
Therefore, 68.0% of the athletes took more than 26 seconds to finish the race.
1. Identify the relevant intervals:
- We need to consider athletes who took more than 26 seconds. This includes the time intervals [tex]$26 < t \leq 28$[/tex] and [tex]$28 < t \leq 30$[/tex].
2. Count the number of athletes in each interval:
- For [tex]$26 < t \leq 28$[/tex], there are 8 athletes.
- For [tex]$28 < t \leq 30$[/tex], there are 9 athletes.
3. Add the number of athletes in these intervals:
- Total athletes taking more than 26 seconds = 8 (from [tex]$26 < t \leq 28$[/tex]) + 9 (from [tex]$28 < t \leq 30$[/tex]) = 17 athletes.
4. Find the total number of athletes:
- Sum the frequencies of all intervals:
- [tex]$22 < t \leq 24$[/tex]: 3 athletes
- [tex]$24 < t \leq 26$[/tex]: 5 athletes
- [tex]$26 < t \leq 28$[/tex]: 8 athletes
- [tex]$28 < t \leq 30$[/tex]: 9 athletes
- Total athletes = 3 + 5 + 8 + 9 = 25 athletes.
5. Calculate the percentage of athletes who took more than 26 seconds:
- Use the formula for percentage:
[tex]\[
\text{Percentage} = \left(\frac{\text{Number of athletes who took more than 26 seconds}}{\text{Total number of athletes}}\right) \times 100
\][/tex]
- Substitute the values into the formula:
[tex]\[
\text{Percentage} = \left(\frac{17}{25}\right) \times 100 = 68.0\%
\][/tex]
Therefore, 68.0% of the athletes took more than 26 seconds to finish the race.
Thanks for taking the time to read The table below shows the times taken for a group of athletes to finish a 200 m race Work out the percentage of the athletes. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada
