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What is the exponential form of the equation [tex]z = \log_{94} y[/tex]?

A. [tex]94 = z^y[/tex]

B. [tex]94^z = y[/tex]

C. [tex]94^y = z[/tex]

D. [tex]94 = y^2[/tex]

Answer :

Sure, let's work through this step-by-step.

The given logarithmic equation is:
[tex]\[ z = \log_{94} y \][/tex]

We need to express this equation in its exponential form.

In general, if you have a logarithmic equation of the form:
[tex]\[ a = \log_b c \][/tex]

Its equivalent exponential form is:
[tex]\[ b^a = c \][/tex]

Applying this to our specific equation, we have:
[tex]\[ z = \log_{94} y \][/tex]

Here:
- [tex]\( a \)[/tex] is [tex]\( z \)[/tex]
- [tex]\( b \)[/tex] is [tex]\( 94 \)[/tex]
- [tex]\( c \)[/tex] is [tex]\( y \)[/tex]

So, the exponential form will be:
[tex]\[ 94^z = y \][/tex]

Therefore, the correct answer is:
(B) [tex]\( 94^z = y \)[/tex]

Thanks for taking the time to read What is the exponential form of the equation tex z log 94 y tex A tex 94 z y tex B tex 94 z y. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

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