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The atmospheric pressures at the top and the bottom of a mountain are read by a barometer to be 93.8 kPa and 100.5 kPa. If the average density of air is 1.25 kg/m\(^3\), what is the height of the mountain?

Answer :

Answer:

546.94 meters is the height of the mountain.

Step-by-step explanation:

Pressure at the top of mountain = [tex]P_1=93.8 kPa[/tex]

Pressure at the bottom of the mountain = [tex]P_2=100.5 kPa[/tex]

Pressure difference =[tex]P_2-P_1=100.5kPa-93.8kPa=6.7 kPa[/tex]

6.7 kPa = 6.7 × 1000 Pa (1 kPa= 1000 pa)

Density of the air = d = [tex]1.25 kg/m^3[/tex]

Acceleration due to gravity = g = [tex]9.8 m/s^2[/tex]

Height of the mountain = h

[tex]P=h\times d\times g[/tex]

[tex]h=\frac{P}{d\times g}=\frac{6.7\times 1000 Pa}{1.25 kg/m^3\times 9.8 m/s^2}[/tex]

[tex]h=546.94 m[/tex]

546.94 meters is the height of the mountain.

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