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A dose of 30 mEq KCl has been added to 1 L of normal saline.

What drip rate would provide a patient with 2 mEq KCl/hr?

Answer: _____ ml/hr

Answer :

The drip rate for normal saline that would provide a patient with 2 mEq KCl/hr is 60 ml/hr.

How to find dosage?

Total volume of solution = 1 L = 1000 ml

KCl concentration = 30 mEq/L

KCl desired delivery rate = 2 mEq/hr

To calculate the drip rate, know the volume of KCl that needs to be delivered per hour. We can do this by multiplying the KCl desired delivery rate by the KCl concentration:

Volume of KCl/hr = KCl desired delivery rate (mEq/hr) x KCl concentration (mEq/L)

Volume of KCl/hr = 2 mEq/hr x 30 mEq/L

Volume of KCl/hr = 60 mEq/hr

The drip rate is the volume of solution that needs to be delivered per hour divided by the total volume of solution.

Drip rate (ml/hr) = Volume of KCl/hr / Total volume of solution (ml)

Drip rate (ml/hr) = 60 mEq/hr / 1000 ml

Drip rate (ml/hr) = 0.06 ml/hr

Therefore, the drip rate that would provide a patient with 2 mEq KCl/hr is 0.06 ml/hr.

Find out more on normal saline here: https://brainly.com/question/30745183

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