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Answer :
We start with an initial area given by
$$
A_0 = 58 \text{ m}^2.
$$
Each hour, the area increases by 13%, which means the area is multiplied by
$$
1 + 0.13 = 1.13
$$
every hour. Thus, after 20 hours, the area covered by the fire is given by the exponential growth formula
$$
A = A_0 \cdot \left(1.13\right)^{20}.
$$
Substituting the initial value, we have
$$
A = 58 \cdot \left(1.13\right)^{20}.
$$
Evaluating the expression gives an exact area of approximately
$$
668.3390903539545 \text{ m}^2.
$$
Rounding to the nearest $1 \text{ m}^2$, the area is
$$
668 \text{ m}^2.
$$
Thus, the fire will cover approximately $668 \text{ m}^2$ in 20 hours.
$$
A_0 = 58 \text{ m}^2.
$$
Each hour, the area increases by 13%, which means the area is multiplied by
$$
1 + 0.13 = 1.13
$$
every hour. Thus, after 20 hours, the area covered by the fire is given by the exponential growth formula
$$
A = A_0 \cdot \left(1.13\right)^{20}.
$$
Substituting the initial value, we have
$$
A = 58 \cdot \left(1.13\right)^{20}.
$$
Evaluating the expression gives an exact area of approximately
$$
668.3390903539545 \text{ m}^2.
$$
Rounding to the nearest $1 \text{ m}^2$, the area is
$$
668 \text{ m}^2.
$$
Thus, the fire will cover approximately $668 \text{ m}^2$ in 20 hours.
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