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Answer :
To solve the problem of how long it takes Erik to shell 2 pounds of peas, we can use the given relationship between the time spent shelling peas, [tex]\(x\)[/tex] (in minutes), and the weight of the peas shelled, [tex]\(y\)[/tex] (in pounds). The relationship is described by the equation:
[tex]\[ y = 0.2x \][/tex]
Here, [tex]\(0.2\)[/tex] is the proportionality constant, which tells us how many pounds of peas Erik shells per minute.
We are given that the weight of the peas Erik shells, [tex]\(y\)[/tex], is 2 pounds, and we need to find the time, [tex]\(x\)[/tex], it takes for him to shell these peas. We can substitute [tex]\(y\)[/tex] with 2 in the equation and solve for [tex]\(x\)[/tex]:
[tex]\[ 2 = 0.2x \][/tex]
To find [tex]\(x\)[/tex], we divide both sides of the equation by 0.2:
[tex]\[ x = \frac{2}{0.2} \][/tex]
By calculating the division, we find:
[tex]\[ x = 10 \][/tex]
Therefore, it takes Erik 10 minutes to shell 2 pounds of peas.
[tex]\[ y = 0.2x \][/tex]
Here, [tex]\(0.2\)[/tex] is the proportionality constant, which tells us how many pounds of peas Erik shells per minute.
We are given that the weight of the peas Erik shells, [tex]\(y\)[/tex], is 2 pounds, and we need to find the time, [tex]\(x\)[/tex], it takes for him to shell these peas. We can substitute [tex]\(y\)[/tex] with 2 in the equation and solve for [tex]\(x\)[/tex]:
[tex]\[ 2 = 0.2x \][/tex]
To find [tex]\(x\)[/tex], we divide both sides of the equation by 0.2:
[tex]\[ x = \frac{2}{0.2} \][/tex]
By calculating the division, we find:
[tex]\[ x = 10 \][/tex]
Therefore, it takes Erik 10 minutes to shell 2 pounds of peas.
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