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Ms. Burns makes a shot on goal, sending the 0.49 kg puck flying to the left at 41 m/s. It bounces off of Ms. Leach, the goalie, ending up going to the right at 5 m/s. If Ms. Leach felt a force of 139 N, how long did the impulse take?

Answer :

Final answer:

To find the duration of the impulse, we calculated the change in momentum of the hockey puck and then used the impulse-momentum theorem with the provided force to find the time duration, which is approximately 0.162 seconds.

Explanation:

The student is asking about the duration of an impulse exerted on a hockey puck by a goalie during a game. To answer this question, we use the impulse-momentum theorem, which states that the impulse on an object is equal to the change in its momentum, and impulse is also the product of the average force and the time the force is applied. We start by calculating the change in momentum of the puck as it moves from 41 m/s to the left to 5 m/s to the right:

Δp = m(v_f - v_i)
Δp = 0.49 kg (5 m/s - (-41 m/s))
Δp = 0.49 kg (46 m/s) = 22.54 kg·m/s

Then, we calculate the time duration (Δt) of the impulse using the formula:

Impulse = Force × Time
22.54 kg·m/s = 139 N × Δt
Δt = 22.54 kg·m/s / 139 N

Δt = 0.162 seconds (rounded to three significant figures)

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