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Which line is perpendicular to a line that has a slope of [tex]-\frac{5}{6}[/tex]?

A. Line JK
B. Line LM
C. Line NO
D. Line PQ

Answer :

To find the line that is perpendicular to a line with a slope of [tex]\(-\frac{5}{6}\)[/tex], we need to calculate the negative reciprocal of the given slope.

1. Identify the original slope: The slope of the original line is [tex]\(-\frac{5}{6}\)[/tex].

2. Find the negative reciprocal:
- To find the negative reciprocal of a slope, you invert the fraction and change its sign.
- The reciprocal of [tex]\(-\frac{5}{6}\)[/tex] is [tex]\(-\frac{6}{5}\)[/tex].
- To get the negative reciprocal, change the sign: [tex]\(\frac{6}{5}\)[/tex].

So, a line that is perpendicular to one with a slope of [tex]\(-\frac{5}{6}\)[/tex] will have a slope of [tex]\(\frac{6}{5}\)[/tex].

Now, you need to identify which of the given lines (JK, LM, NO, or PQ) has a slope of [tex]\(\frac{6}{5}\)[/tex]. Please check the equations or other given properties for each of these lines to determine which one has this slope.

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